10 October
2013
Puzzle – alligation?
While it is not exactly about mixing liquids, it involves pouring liquids alright.
You have three containers whose capacity are 12 gallons, 8 gallons and 5 gallons respectively. The 12 gallon container is filled with water and the other two are empty. You have nothing else. You have to divide the water into two parts of 6 gallons each. In other words, by a sequence of pouring from one container to the other, you have to eventually have 6 gallons in the 12 gallon container and another 6 gallons in the 8 gallon container.
How would you do it?
I’d pay someone smart.
Sara, feel free to send me the check 🙂 Oh! You said “smart” 🙂
I might work that hard for vodka but water? Nah.
For vodka, I am afraid you will be unwilling to share the other 6 gallons 🙂
Ha 🙂 Yeah, you know me, all right
How can I send the answer?
Madhu, I should have repeated the rules from the past. You do not post answers on comments section. Send a personal message to me, this allows others to try. The answer, however is correct!
Rupa cracked the problem!!
Shoma, presumably from Las Vegas, also sent the right answer. 🙂
Took 10 minutes and a sheet of paper to figure it out…I’m slipping.
I am on it for more than 10 minutes on multiple sheets of paper. Could not crack it. Forwarded to Esha. Will keep working it.
Milind and Dilesh cracked it too!
I sent Esha back to doing HW. She asked me not to tell her the solution if I knew how to do it. I haven’t figured out yet.
Rajib its an old puzle
12 = 4 +8 + 0
= 4 + 3 + 5
= 9 + 3 + 0
= 9 + 0 + 3
= 1 + 8 + 3
= 1 + 6 + 5
= 6 + 6
Debasis, dude you are not supposed to send answers on the comment section. The answer is right though
Amitesh and Deepak got it too.
Srini go it too
Answer to the puzzle:
start with: 12 – 0 – 0
pour from first to second 4 – 8 – 0
pour from second to third 4 – 3 – 5
pour from third to first 9 – 3 – 0
pour from second to third 9 – 0 – 3
pour from first to second 1 – 8 – 3
pour from second to third 1 – 6 – 5
pour from third to first 6 – 6 – 0 !!