10 October 2013

# Puzzle – alligation?

While it is not exactly about mixing liquids, it involves pouring liquids alright.
You have three containers whose capacity are 12 gallons, 8 gallons and 5 gallons respectively. The 12 gallon container is filled with water and the other two are empty. You have nothing else. You have to divide the water into two parts of 6 gallons each. In other words, by a sequence of pouring from one container to the other, you have to eventually have 6 gallons in the 12 gallon container and another 6 gallons in the 8 gallon container.
How would you do it?

Posted October 10, 2013 by Rajib Roy in category "Puzzles

1. By Rajib Roy (Post author) on

For vodka, I am afraid you will be unwilling to share the other 6 gallons π

2. By Rajib Roy (Post author) on

Madhu, I should have repeated the rules from the past. You do not post answers on comments section. Send a personal message to me, this allows others to try. The answer, however is correct!

3. By Amitesh Mukherjee (Post author) on

I am on it for more than 10 minutes on multiple sheets of paper. Could not crack it. Forwarded to Esha. Will keep working it.

4. By Amitesh Mukherjee (Post author) on

I sent Esha back to doing HW. She asked me not to tell her the solution if I knew how to do it. I haven’t figured out yet.

5. By Rajib Roy (Post author) on

Debasis, dude you are not supposed to send answers on the comment section. The answer is right though

6. By Rajib Roy (Post author) on